[DiscordArchive] What's the right way to call CSMH's SendServerResponse from C++?
[DiscordArchive] What's the right way to call CSMH's SendServerResponse from C++?
Original source
What's the right way to call CSMH's SendServerResponse from C++?
rektbyfaith
07-09-2022, 07:36 PM #1Archived author: whatwere • Posted: 2022-07-09T19:36:09.137000+00:00
Original source
What's the right way to call CSMH's SendServerResponse from C++?
Original source
Finally my dream come true, i can do this :
```cpp
class A
{
public:
...
void setFunction(std::function<void()> param)
{
my_access = param;
}
void run()
{
...
my_access();
}
private:
std::function<void()> my_access;
}
class B
{
public:
void anotherFunc()
{
A* myclassA = new A();
std::function<void()> func1 = [this]() {
std::cout << "Hello" << std::endl;
};
std::function<void()> func2 = [this]() {
std::cout << "Bye bye" << std::endl;
};
myClassA->setFunction(func1);
myClassA->run(); // return <Hello>
myClassB->setFunction(func2);
myClassB->run(); // return <Bye bye>
}
}
```
rektbyfaith
07-09-2022, 07:46 PM #2Archived author: Intemporel • Posted: 2022-07-09T19:46:27.025000+00:00
Original source
Finally my dream come true, i can do this :
```cpp
class A
{
public:
...
void setFunction(std::function<void()> param)
{
my_access = param;
}
void run()
{
...
my_access();
}
private:
std::function<void()> my_access;
}
class B
{
public:
void anotherFunc()
{
A* myclassA = new A();
std::function<void()> func1 = [this]() {
std::cout << "Hello" << std::endl;
};
std::function<void()> func2 = [this]() {
std::cout << "Bye bye" << std::endl;
};
myClassA->setFunction(func1);
myClassA->run(); // return <Hello>
myClassB->setFunction(func2);
myClassB->run(); // return <Bye bye>
}
}
```
Original source
if they don't have to be member functions then yeah, you can capture scope variables (including "this") like that
rektbyfaith
07-09-2022, 07:48 PM #3Archived author: <o> • Posted: 2022-07-09T19:48:25.864000+00:00
Original source
if they don't have to be member functions then yeah, you can capture scope variables (including "this") like that
Original source
i can do this because `std::function<>` is a type, i can capture any object like that, add any param etc... it's work
rektbyfaith
07-09-2022, 07:49 PM #4Archived author: Intemporel • Posted: 2022-07-09T19:49:27.469000+00:00
Original source
i can do this because `std::function<>` is a type, i can capture any object like that, add any param etc... it's work
Original source
that's the magic you normally get with std functions, but just be careful so you actually keep the reference around because that is not ensured (i.e. you'll crash if the B variable goes out of scope and you try to call the function).
rektbyfaith
07-09-2022, 07:53 PM #5Archived author: <o> • Posted: 2022-07-09T19:53:02.172000+00:00
Original source
that's the magic you normally get with std functions, but just be careful so you actually keep the reference around because that is not ensured (i.e. you'll crash if the B variable goes out of scope and you try to call the function).
Original source
you can also capture other variables like that, both by value and by reference:
```c++
int val1 = 0;
std::function<void()> f0 = [val1]() { std::cout << val1 << "\n"; }
std::function<void()> f1 = [&val1]() { std::cout << val1 << "\n"; }
```
rektbyfaith
07-09-2022, 07:54 PM #6Archived author: <o> • Posted: 2022-07-09T19:54:12.937000+00:00
Original source
you can also capture other variables like that, both by value and by reference:
```c++
int val1 = 0;
std::function<void()> f0 = [val1]() { std::cout << val1 << "\n"; }
std::function<void()> f1 = [&val1]() { std::cout << val1 << "\n"; }
```
Original source
capture by value and the lambda will itself keep a copy of the variable in its own scope, but that doesn't help if it's just a pointer of course
rektbyfaith
07-09-2022, 07:55 PM #7Archived author: <o> • Posted: 2022-07-09T19:55:12.068000+00:00
Original source
capture by value and the lambda will itself keep a copy of the variable in its own scope, but that doesn't help if it's just a pointer of course
Original source
Class A is initialised and used only by and in class B, in this way i think i can't go out of scope, generally i only need to capture this
rektbyfaith
07-09-2022, 08:04 PM #8Archived author: Intemporel • Posted: 2022-07-09T20:04:37.922000+00:00
Original source
Class A is initialised and used only by and in class B, in this way i think i can't go out of scope, generally i only need to capture this
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