[DiscordArchive] Are you kinda smoke ? Did you calculate this ?
[DiscordArchive] Are you kinda smoke ? Did you calculate this ?
Original source
Are you kinda smoke ? Did you calculate this ?
rektbyfaith
07-17-2023, 05:49 PM #1Archived author: Seyden • Posted: 2023-07-17T17:49:05.569000+00:00
Original source
Are you kinda smoke ? Did you calculate this ?
Original source
i did
rektbyfaith
07-17-2023, 05:49 PM #2Archived author: Telegrill • Posted: 2023-07-17T17:49:10.623000+00:00
Original source
i did
Original source
You can basically remove the 0
rektbyfaith
07-17-2023, 05:49 PM #3Archived author: Seyden • Posted: 2023-07-17T17:49:12.940000+00:00
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You can basically remove the 0
Original source
radius = 0.f + (baseRadius - 0.f) * GetCurveValueAt(CurveScaleId, GetProgress());
=>
radius *= GetCurveValueAt(curveScaleId, GetProgress());
That's like exactly the same math
rektbyfaith
07-17-2023, 05:49 PM #4Archived author: Traesh • Posted: 2023-07-17T17:49:15.652000+00:00
Original source
radius = 0.f + (baseRadius - 0.f) * GetCurveValueAt(CurveScaleId, GetProgress());
=>
radius *= GetCurveValueAt(curveScaleId, GetProgress());
That's like exactly the same math
Original source
Exactly
rektbyfaith
07-17-2023, 05:49 PM #5Archived author: Seyden • Posted: 2023-07-17T17:49:21.929000+00:00
Original source
Exactly
Original source
yeah but I'm bad at maths and removing stuff for me makes it unclear
rektbyfaith
07-17-2023, 05:49 PM #6Archived author: Telegrill • Posted: 2023-07-17T17:49:55.554000+00:00
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yeah but I'm bad at maths and removing stuff for me makes it unclear
Original source
You‘re weird
rektbyfaith
07-17-2023, 05:50 PM #7Archived author: Seyden • Posted: 2023-07-17T17:50:02.557000+00:00
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You‘re weird
Original source
hence why I barely use *=
rektbyfaith
07-17-2023, 05:50 PM #8Archived author: Telegrill • Posted: 2023-07-17T17:50:06.627000+00:00
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hence why I barely use *=
Original source
It’s literally 0 + (1 - 0)
rektbyfaith
07-17-2023, 05:50 PM #9Archived author: Seyden • Posted: 2023-07-17T17:50:17.293000+00:00
Original source
It’s literally 0 + (1 - 0)
Original source
0*x+y is always = y
rektbyfaith
07-17-2023, 05:50 PM #10Archived author: ModoX • Posted: 2023-07-17T17:50:20.690000+00:00
Original source
0*x+y is always = y
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